Solving $x^{2^k+1}+x+a=0$ in $\mathbb{F}_{2^n}$ with $\gcd(n,k)=1$

K. H. Kim; Sihem Mesnager

Journal articles

Solving $x^{2^k+1}+x+a=0$ in $\mathbb{F}_{2^n}$ with $\gcd(n,k)=1$

K. H. Kim Sihem Mesnager ^{1, 2, 3, 4}

1 UP8 - Université Paris 8 Vincennes-Saint-Denis

2 INFRES - Département Informatique et Réseaux

3 MC2 - Mathématiques discrètes, Codage et Cryptographie

LTCI - Laboratoire Traitement et Communication de l'Information

4 IP Paris - Institut Polytechnique de Paris

Document type :

Journal articles

Domain :

Mathematics [math]

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https://hal.telecom-paris.fr/hal-03048680
Contributor : Olivier Hudry Connect in order to contact the contributor
Submitted on : Wednesday, December 9, 2020 - 2:50:03 PM
Last modification on : Monday, January 24, 2022 - 8:26:29 AM

Solving $x^{2^k+1}+x+a=0$ in $\mathbb{F}_{2^n}$ with $\gcd(n,k)=1$

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Solving $x^{2^k+1}+x+a=0$ in $\mathbb{F}_{2^n}$ with $\gcd(n,k)=1$

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