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Solving $x+x^{2^l}+\cdots+x^{2^{ml}}=a$ over $\mathbb{F}_{2^n}$.

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Contributor : Olivier Hudry Connect in order to contact the contributor
Submitted on : Friday, December 11, 2020 - 11:38:38 AM
Last modification on : Monday, January 24, 2022 - 8:26:29 AM


  • HAL Id : hal-03053979, version 1


Sihem Mesnager, K.H. Kim, J.H. Choe, D.N. Lee, D.S. Go. Solving $x+x^{2^l}+\cdots+x^{2^{ml}}=a$ over $\mathbb{F}_{2^n}$.. Cryptography and Communications-Discrete Structures, Boolean Functions, and Sequences (CCDS), 2020. ⟨hal-03053979⟩



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